x^2-32x-52=0

Solution for x^2-32x-52=0 equation:

x^2-32x-52=0

a = 1; b = -32; c = -52;
Δ = b2-4ac
Δ = -322-4·1·(-52)
Δ = 1232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1232}=\sqrt{16*77}=\sqrt{16}*\sqrt{77}=4\sqrt{77}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{77}}{2*1}=\frac{32-4\sqrt{77}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{77}}{2*1}=\frac{32+4\sqrt{77}}{2}
$